2(x-2)+3x=2(x+1)+2^2

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Solution for 2(x-2)+3x=2(x+1)+2^2 equation: 



2(x-2)+3x=2(x+1)+2^2

We move all terms to the left:

2(x-2)+3x-(2(x+1)+2^2)=0

We add all the numbers together, and all the variables

3x+2(x-2)-(2(x+1)+2^2)=0

We multiply parentheses

3x+2x-(2(x+1)+2^2)-4=0



We calculate terms in parentheses: -(2(x+1)+2^2), so:

2(x+1)+2^2

We add all the numbers together, and all the variables

2(x+1)+4

We multiply parentheses

2x+2+4

We add all the numbers together, and all the variables

2x+6

Back to the equation:

-(2x+6)



We add all the numbers together, and all the variables

5x-(2x+6)-4=0

We get rid of parentheses

5x-2x-6-4=0

We add all the numbers together, and all the variables

3x-10=0

We move all terms containing x to the left, all other terms to the right

3x=10

x=10/3

x=3+1/3

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